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600+14x-16x^2=0
a = -16; b = 14; c = +600;
Δ = b2-4ac
Δ = 142-4·(-16)·600
Δ = 38596
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{38596}=\sqrt{4*9649}=\sqrt{4}*\sqrt{9649}=2\sqrt{9649}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{9649}}{2*-16}=\frac{-14-2\sqrt{9649}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{9649}}{2*-16}=\frac{-14+2\sqrt{9649}}{-32} $
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